Inflection Point Calculator

Find where a curve switches from cupped up to cupped down. Get f″, the candidates, the sign test and the concavity intervals, shaded on the graph.

Reads as x4−6x2x^{4} - 6 x^{2}
Try:

Inflection points

(−1, −5),(1, −5)(-1,\ -5),\quad (1,\ -5)

Concave up on (-3, -1) ∪ (1, 3); concave down on (-1, 1).

-3-2-1123-10102030
  • f
  • f″
∪ up∩ down∪ up

Step by step

  1. First derivative

    f′(x)=4x3−12xf'(x) = 4 x^{3} - 12 x
  2. Second derivative

    f′′(x)=12x2−12f''(x) = 12 x^{2} - 12
  3. Solve f″(x) = 0

    x=−1,x=1x = -1,\quad x = 1
  4. Test the sign of f″ on each side

    concave up on (−3,−1)(-3, -1); concave down on (−1,1)(-1, 1); concave up on (1,3)(1, 3).

  5. Inflection points

    Only candidates where the sign actually changes count.

    (−1, −5), (1, −5)(-1,\ -5),\ (1,\ -5)

Still stuck? Ask the tutor

An AI tutor reads the problem and steps above and explains them in plain words. It can make mistakes, so check it against the worked steps.

Concavity in one picture

Concave up (f′′>0f'' > 0) means the slope is increasing: the curve bends like a cup, and tangent lines sit below it. Concave down (f′′<0f'' < 0) means the slope is decreasing: the curve bends like a cap. The inflection point is the moment of switching, which is also where f′f' reaches a local max or min.

To find the second derivative with every rule shown, use the second derivative calculator.

Questions students ask

What is an inflection point?

A point on the graph where the concavity changes: from cupped up (concave up, f′′>0f'' > 0) to cupped down (f′′<0f'' < 0), or the reverse.

If f″(c) = 0, is c always an inflection point?

No. f(x)=x4f(x) = x^4 has f′′(0)=0f''(0) = 0 but is concave up on both sides, so there is no inflection point. The sign of f′′f'' must actually change, which is why the calculator checks both sides.

What does an inflection point mean in real life?

It is where a rate of change is itself at a max or min. For example, where an epidemic curve stops accelerating, or where a car stops speeding up and starts slowing its acceleration.

Can an inflection point occur where f″ is undefined?

Yes, for example f(x)=x1/3f(x) = x^{1/3} at 0: f′′f'' does not exist there but the concavity flips. Check such points separately.