The Power Rule

Bring the exponent down, knock one off the exponent. It is the rule you’ll use more than any other, and it works for every power, not just whole numbers.

ddx xn=n xn−1\frac{d}{dx}\,x^n = n\,x^{n-1}

Check it yourself

The graph measures the slope of xnx^n numerically, as rise over a tiny run, and compares it with what the rule predicts. Change nn, drag the point, and see if you can break it:

0.511.522.5123456

Measured slope at x = 1.20: 4.32

Power rule nxn−1=3⋅1.202n x^{n-1} = 3 \cdot 1.20^{2} = 4.32

Try fractional and negative n: the rule keeps matching the measured slope.

Worked examples

FunctionRewrite as a powerDerivative
x5x^5x5x^55x45x^4
7x37x^37x37x^321x221x^2
x\sqrt{x}x1/2x^{1/2}12x−1/2=12x\tfrac12 x^{-1/2} = \tfrac{1}{2\sqrt x}
1x2\frac{1}{x^2}x−2x^{-2}−2x−3=−2x3-2x^{-3} = -\tfrac{2}{x^3}
x23\sqrt[3]{x^2}x2/3x^{2/3}23x−1/3\tfrac23 x^{-1/3}
4x−1/24x^{-1/2}4x−1/24x^{-1/2}−2x−3/2-2x^{-3/2}

Why it works

From the definition of the derivative with n=3n = 3:

(x+h)3−x3h=3x2h+3xh2+h3h=3x2+3xh+h2  →  3x2\frac{(x+h)^3 - x^3}{h} = \frac{3x^2h + 3xh^2 + h^3}{h} = 3x^2 + 3xh + h^2 \;\to\; 3x^2

For any whole nn, the binomial theorem gives (x+h)n=xn+nxn−1h+…(x+h)^n = x^n + nx^{n-1}h + \dots, and every term after the second has h2h^2 or more, so it vanishes. For fractional and negative powers the same result follows from implicit differentiation or from xn=enln⁡xx^n = e^{n\ln x}.

The power rule for integrals

Run it backwards: ∫xn dx=xn+1n+1+C\int x^n\,dx = \frac{x^{n+1}}{n+1} + C, except n=−1n = -1, where it would divide by zero and the answer is ln⁡∣x∣+C\ln|x| + C instead. More on integration rules.

Still stuck? Ask the tutor

An AI tutor reads the problem and steps above and explains them in plain words. It can make mistakes, so check it against the worked steps.

Questions students ask

What is the power rule for derivatives?

ddxxn=n xn−1\frac{d}{dx}x^n = n\,x^{n-1}: bring the exponent down in front, then subtract one from the exponent. It works for every real nn: whole numbers, fractions and negatives.

How do I use it on roots and fractions?

Rewrite them as powers first. x=x1/2\sqrt{x} = x^{1/2} gives 12x−1/2=12x\frac12 x^{-1/2} = \frac{1}{2\sqrt{x}}. 1x3=x−3\frac{1}{x^3} = x^{-3} gives −3x−4-3x^{-4}.

What is the power rule for integrals?

The reverse: ∫xn dx=xn+1n+1+C\int x^n\,dx = \frac{x^{n+1}}{n+1} + C for n≠−1n \ne -1. Add one to the exponent, then divide by the new exponent. For n=−1n = -1 the answer is ln⁡∣x∣+C\ln|x| + C.

Why does the power rule work?

For whole numbers, expand (x+h)n=xn+nxn−1h+(terms with h2)(x+h)^n = x^n + n x^{n-1} h + (\text{terms with } h^2). Subtract xnx^n, divide by hh, let h→0h \to 0: only nxn−1n x^{n-1} survives.